logic01 peking univ
回答: 勒贝格积分 采取对值域作分划,相应得到对定义域的分划(每一块不一定是区间), 使得在每一块上的振幅都很小, 即按函数值的大小对定
由 marketreflections
于 2011-10-05 15:03:35
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