No. But the integral takes place over the entire space. Silly

来源: weston 于 2015-03-07 11:22:38 [] [博客] [旧帖] [给我悄悄话] 阅读数 : (0 bytes)

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• Then look at your insisting on including the zero-valued subspac -career- ♂ 给 career 发送悄悄话 (125 bytes) () 03/07/2015 postreply 11:29:43

• You learned Fourier by skipping all non-zero values of a functio -weston- ♀ 给 weston 发送悄悄话 weston 的博客首页 (0 bytes) () 03/07/2015 postreply 11:42:21

• Show me where I did that? :) -career- ♂ 给 career 发送悄悄话 (0 bytes) () 03/07/2015 postreply 11:48:47

• Out of (-.5, 0.5), rect's Lebesgue measure is zero:) -career- ♂ 给 career 发送悄悄话 (200 bytes) () 03/07/2015 postreply 12:16:05

• Repeat one more time: Go and study Bochner Theorem (actually -weston- ♀ 给 weston 发送悄悄话 weston 的博客首页 (35 bytes) () 03/07/2015 postreply 12:26:42

• Bochner/ Lebesgue won't CYA :) -career- ♂ 给 career 发送悄悄话 (813 bytes) () 03/07/2015 postreply 12:40:48

• Gave you the math definition already. Your comment adds nothing -weston- ♀ 给 weston 发送悄悄话 weston 的博客首页 (0 bytes) () 03/07/2015 postreply 13:07:01

• Got your "Say it the 3rd time, rec funcition is a step function. -career- ♂ 给 career 发送悄悄话 (80 bytes) () 03/07/2015 postreply 13:10:25

• Too bad, you can't read math -weston- ♀ 给 weston 发送悄悄话 weston 的博客首页 (0 bytes) () 03/07/2015 postreply 14:22:16

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