得出的解是
Vn = Z e2 / 2ε0 n h
Z = 原子数 氢=1, 氦=2
n = 电子能级,1到无穷大
h = 普朗克常数
得出的解是
Vn = Z e2 / 2ε0 n h
Z = 原子数 氢=1, 氦=2
n = 电子能级,1到无穷大
h = 普朗克常数
                    •                    
                    能不能问一下你这些问题是干嘛用的啊?
                     -viewfinder- 
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                        11/23/2011 postreply
                                                14:20:06
                    
                    
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                    原子数-->原子序数
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                        11/23/2011 postreply
                                                14:25:21
                    
                    
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                    上面的意思就是更正,要把”原子数“改成”原子序数“
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                        11/24/2011 postreply
                                                13:49:29
                    
                    
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                    V是速度?
                     -qiasini- 
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                        11/23/2011 postreply
                                                18:46:23
                    
                    
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                    是的
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                        11/24/2011 postreply
                                                13:49:59
                    
                    
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