thanks

来源: NIWbaby 于 2009-05-15 14:18:56 [] [旧帖] [给我悄悄话] 阅读数 : (171 bytes)
回答: J2 question,please 由 NIWbaby 于 2009-05-15 08:39:14

Thanks, Your meaning is the same as my theory: j2 always follow j1. Once j1 completed the 2-yr service, j-2 does not have to completed the 2-yr service.

Am I right?

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