thanks

来源: 于 2009-05-15 14:18:56 [旧帖] [给我悄悄话] 本文已被阅读：次

Thanks, Your meaning is the same as my theory: j2 always follow j1. Once j1 completed the 2-yr service, j-2 does not have to completed the 2-yr service.

Am I right?