都不难,OPEN 一个RECORDSET就可以了找到最大,再开一个找到最后。然后再开一个RECORDSET,显示出每一个为0的,然后负值就可以了
都不难,OPEN 一个RECORDSET就可以了找到最大,再开一个找到最后。然后再开一个RECORDSET,显示出每一个为0的,然后负值就可以了
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