Problem 1: There are 10 parking spaces in a line adjacent to one another, and 3 identical cars come to the parking lot. They do not wish to park next to any other car. How many ways can they do this?
Problem 2: There are 8 parking spaces in a line adjacent to one another, and 3 identical cars come to the parking lot. How many ways can they do this?
Note: In Problem 2, there is no restriction "They do not wish to park next to any other car".
It is easy to solve Problem 2, and the answer is C(8,3) = 56.
We will argue that Problems 1 and 2 have the same answer by establishing a one-to-one correspondence between the ways of parking in Problem 1 and the ways of parking in Problem 2. For each way of parking in Problem 1, taking away one parking space from the left of the middle car and another one from the right yields one way of parking in Problem 2. Conversely, for each way of parking in Problem 2, adding one parking space to the left of the middle car and another one to the right yields one way of parking in Problem 1. Hence, the answer to Problem 1 is also 56.