1, 2, 3, ...
2, 4, 6, ...
.....
m, 2m, 3m,....
.....
the sume of the first term is
m + 2m + .... + 10m = 55m, where m is any integer
so all the sums are devisible by 55 and its factors (1,5,10,11, 55) and 55 is the greated numbers that can devide all the sums.