Totally, 4 real roots.

来源: 2024-01-25 17:42:55 [博客] [旧帖] [给我悄悄话] 本文已被阅读:

Let f(x) =  (x^2 - 6x +5)(x^2 + 3x + 3) - (x^2 - 2x - 3)(2 -3x) = x^4 - 18x^2 - 8x + 21

 

f(-4) = 21, f(-3) = -36, so there is a root in the interval (-4, -3)

 

f(-2)= -21, f(-1) = 12, so there is a root in (-2, -1)

 

f(0) = 21, f(1) = -4, so there is a root in (0, 1)

 

f(4) = -43, f(5) = 164, so there is a root in (4, 5)

 

Totally, 4 real roots. These are all the possible roots since f(x) is a polynomial of degree 4.