回复:1,9,31,73,141...下一个数字是什么?

来源: 2005-01-13 10:51:25 [旧帖] [给我悄悄话] 本文已被阅读:
It can be any number.It is easy to get a polynomial to pass through points (1,1)(2,9)(3,31)(4,73)(5,141)(6,a),a is any number.