对称数是指12321之类的、颠倒书写顺序仍不变的自然数。对称平方数是指它是对称数同时还是某个自然数的平方。有人证实698896是
最小偶数位对称平方数(=836^2)。请各位高手编一程序,找出另外两个最小偶数位对称平方数。
---- 以上是一个旧帖子,想跟贴为时已晚。只有重发一个。我原有一个SAS解法在本坛。现用PYTHON再解一遍。答案如下:
836 ^2 = 698896
798644 ^2 = 637832238736
64030648 ^2 = 4099923883299904
83163115486 ^2 = 6916103777337773016196
6360832925898 ^2 = 40460195511188111559106404
69800670077028 ^2 = 4872133543202112023453312784
98275825201587 ^2 = 9658137819052882509187318569
798644 ^2 = 637832238736
64030648 ^2 = 4099923883299904
83163115486 ^2 = 6916103777337773016196
6360832925898 ^2 = 40460195511188111559106404
69800670077028 ^2 = 4872133543202112023453312784
98275825201587 ^2 = 9658137819052882509187318569
希望抛砖引玉