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来源: 于 2012-05-31 12:15:25 [旧帖] [给我悄悄话] 本文已被阅读：次

a=b,令3..PAB,AB的高为t,We have:

t/3=c/2a, (3)^2-t^2=c^2/4 and a^2-(3+t)^2=c^2. cancel a,c, we have Eq:7t^2+2t^3=9.

t=1 , So,..