Answer: A=pirr/arccos((r-h)/r))-(r-h)sqrt(2rh-h*h) where A is

来源: badminton 于 2010-04-20 09:11:29 [旧帖] [给我悄悄话] 本文已被阅读：次

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Answer: A=pi*r*r/arccos((r-h)/r))-(r-h)sqrt(2rh-h*h) where A is