回复：印度奥赛题（2星半）：无穷序列的最大值

(ln(n) * n)' = 1/(n^2) * (1 - ln(n))

which means when n = e = 2.718, the sequence is max. So it's the greater in a = 2^(1/2) and b = 3^(1/3).

a^6 = 8, b^6 = 9. So 3^(1/3).