回复：0^0 = 1

Here is my question. Let y=x^x^x=x^(x^x). when x->0+, (x^x)->1. But the first x goes to 0. 0^1=0. Another way to see it is lny=x^xlnx. when x->0, lny=(1 times -infinity) which is -infinity. So limit y=0. But it seems that your method can show limit y=1.