1) 0^0 = 1 2) Suppose that the sequence f(1) = x, f(2)=x^x, ..., f(n+1)=f(n)^x, then as x->+0, f(2) -> 1. Suppose f(n)^x -> y, as n->00, x->0, then y= f(2)^y, and f(2) ->1 so y->1. Done.