回复：What mistake?

"Let's take a flat stretch of torque curve (e.g. VW's 2.0T between 2k-4k rpm), where Q is constant. In this stretch, P = Q*x. Sure, as your speed V goes up, x goes up, and P goes up. But what about the accelration A? It stays constant because A = P / V = (Q*x) / (Rw/K*x) = Q *(K/Rw), K being gear ratio and Rw being wheel radius. So great, your engine is making more and more power and acceleration stays constant. Is this what you call "directly connected"?"

Again, use your own equation. Q stays constant, A stays constant. V keep going up, P keep going up. What are changing? You tell me! If P stays, V stays as well. Don't tell me V is just the top speed. Let's go back to your 0-60MPH. If Q stays, A stays (for instance 15MPH/S). As long as P keeps up, the A can be maintaned. And 4 Seconds later, it reaches 60MPH! If P didn't go up (in the case of engines that peaks out Q in lower RPM) during this 4 seconds, A becomes 0, and V stops! So, what's maintaining the A? Both Q and P. And Q has to stay as long as possible. That's why lower rpm Q alone is not enough. It has to be kept up to the high rpm to increase HP&V and maintain A.

So, I guess that's what you called "P is not directly related to 加速能力"?

By the way, I never said Q doesn't contribute to A. Hint, proving P is directly contribute to A (maintaining or increasing it) doesn't necessarily disapprove Q is the determine factor too.

Isn't this obvious?