再往下走
a_n
= [(n+1)/(n-1)] a_{n-1}
= [(n+1)n / (n-1)(n-2)] a_{n-2)
= ......
= [(n+1) x n x ... x 4 x 3 / (n-1) x (n-2) x ... x 2 x 1] a_1
= (n+1)n / 2.
再往下走
a_n
= [(n+1)/(n-1)] a_{n-1}
= [(n+1)n / (n-1)(n-2)] a_{n-2)
= ......
= [(n+1) x n x ... x 4 x 3 / (n-1) x (n-2) x ... x 2 x 1] a_1
= (n+1)n / 2.
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