i first calculate the probability a<=b,
(6+5/6+4/6+3/6+2/6+1/6)* 1/6 = 21/36
so it is same probablity for b<=c, c<=d
so (21/36) *(21/36)*(21/36) or (21/36)^3 is the answer
where is wrong?
i first calculate the probability a<=b,
(6+5/6+4/6+3/6+2/6+1/6)* 1/6 = 21/36
so it is same probablity for b<=c, c<=d
so (21/36) *(21/36)*(21/36) or (21/36)^3 is the answer
where is wrong?
• 因为这三个事件不是独立的。a《b就会影响b《c的选择。 -sweetptt- ♂ (0 bytes) () 12/29/2012 postreply 10:05:58
• thanks -smallking- ♂ (0 bytes) () 12/29/2012 postreply 10:13:25
• Sorry for posting the problem -392- ♂ (28 bytes) () 12/29/2012 postreply 10:16:42
• 以后10年教儿子们,不能教错吧,:) -smallking- ♂ (32 bytes) () 12/29/2012 postreply 10:19:33
• 以后10年教儿子们? 你这么年轻? -392- ♂ (32 bytes) () 12/29/2012 postreply 10:22:08
• 帮我,捞一个 -smallking- ♂ (25 bytes) () 12/29/2012 postreply 13:45:40