consider the vertical motion

h = (1/2)gt^2

then: t = squre root of (2h/g) = squre root of (2L*sin(theta)/g)

 

所有跟帖: 

不对,加速度不是常量 -Leileima- 给 Leileima 发送悄悄话 Leileima 的博客首页 (0 bytes) () 12/14/2024 postreply 10:01:18

you want Torque(t)? I thought you want Time (t).. -zeno- 给 zeno 发送悄悄话 (81 bytes) () 12/14/2024 postreply 10:31:24

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