h = (1/2)gt^2
then: t = squre root of (2h/g) = squre root of (2L*sin(theta)/g)
h = (1/2)gt^2
then: t = squre root of (2h/g) = squre root of (2L*sin(theta)/g)
•
不对,加速度不是常量
-Leileima-
♀
(0 bytes)
()
12/14/2024 postreply
10:01:18
•
you want Torque(t)? I thought you want Time (t)..
-zeno-
♀
(81 bytes)
()
12/14/2024 postreply
10:31:24
WENXUECITY.COM does not represent or guarantee the truthfulness, accuracy, or reliability of any of communications posted by other users.
Copyright ©1998-2025 wenxuecity.com All rights reserved. Privacy Statement & Terms of Use & User Privacy Protection Policy