仔细再想,偶数也可二次完成。
1. at A city, 配 (n-2)/2 对,余二根孤线。
2. at B city, 找出对子和二根孤线。
3. at B city, 连接对子和一根孤线成一长线,(见上贴), 余一根孤线。
4. at A city, 先找出那一根孤线,然后再解(见上贴)。
春节快乐!!
• 哦, you have already done that. -guest007- ♀ (19 bytes) () 02/14/2010 postreply 13:07:28
• 回复:哦, you have already done that. -cowgg- ♂ (479 bytes) () 02/18/2010 postreply 17:34:29