A, B, N are positive integers and 2009/2014 + 2019/N = A/B, where A/B is in lowest form and A =0 (mod 1004).
Find sum of digits of the smallest N.
• 9+3+8=20 -keessa- ♀ (65 bytes) () 04/17/2014 postreply 07:31:37
• 回复:9+3+8=20 -wawjmath- ♂ (485 bytes) () 04/17/2014 postreply 08:03:13
• keessa, 2009 N + 2019*2014 is divisible by 16 too. -BeLe- ♀ (0 bytes) () 04/17/2014 postreply 08:59:06
• 2009 N + 2019*2014被1004整除还不够,至少要能被2008整除 -ca981- ♂ (0 bytes) () 04/17/2014 postreply 09:39:25
• 没空,先讨论清楚学习重要性:)) -怪哉- ♂ (0 bytes) () 04/17/2014 postreply 07:32:39
• N = 1942 -BeLe- ♀ (0 bytes) () 04/17/2014 postreply 08:44:16
• 回复:N = 1942 -wawjmath- ♂ (807 bytes) () 04/17/2014 postreply 09:55:41
• 对,最小的是2008-66 = 1942,后面是3950,5958,7966,9974 -ca981- ♂ (118 bytes) () 04/17/2014 postreply 09:26:47
• 回复:对,最小的是2008-66 = 1942,后面是3950,5958,7966,9974 -wawjmath- ♂ (8 bytes) () 04/17/2014 postreply 10:25:11