x= .5^.5^.5^.5^.......^.5^.5^.5^.5^.5^......=x^x.
Thanks a lot. I did not know that you could break one infinite sequence into two like you did above.
You wrote x^x^x^x^....if convergent, We have x=x^x , Lnx=xLnx, we get x=1. So the limit of x^x^x^x^.... is 1 for any x in(0,1]?