回复：0^0 = 1

Here is my question. Let y=x^x^x=x^(x^x). when x->0+, (x^x)->1. But the first x goes to 0. 0^1=0. Another way to see it is lny=x^xlnx. when x->0, lny=(1 times -infinity) which is -infinity. So limit y=0. But it seems that your method can show limit y=1.

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• solution -emlx- ♂ (353 bytes) () 04/29/2007 postreply 16:51:38

• yma16 does have a good question here.. -乱弹- ♂ (215 bytes) () 04/30/2007 postreply 11:27:57

• 回复：yma16 does have a good question here.. -yma16- ♂ (363 bytes) () 04/30/2007 postreply 11:42:41